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	<title>Comments on: Mind Bender # 15 : Solution</title>
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	<link>http://his-best.biz/2008/06/12/mind-bender-15-solution/</link>
	<description>Chris Lang at His Best</description>
	<pubDate>Tue, 06 Jan 2009 06:23:58 +0000</pubDate>
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		<title>By: Chris Lang</title>
		<link>http://his-best.biz/2008/06/12/mind-bender-15-solution/comment-page-1/#comment-322</link>
		<dc:creator>Chris Lang</dc:creator>
		<pubDate>Tue, 17 Jun 2008 02:33:08 +0000</pubDate>
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		<description>Alan -- I think you'll find what I've done is correct.

You see, when you Square the Square Root of "X" ... you actually end up back with "X" (and, in this case, together with the re-occurring component as well).

From there, you're able to substitute for the re-occurring component ... which we know to equal "2".</description>
		<content:encoded><![CDATA[<p>Alan &#8212; I think you&#8217;ll find what I&#8217;ve done is correct.</p>
<p>You see, when you Square the Square Root of &#8220;X&#8221; &#8230; you actually end up back with &#8220;X&#8221; (and, in this case, together with the re-occurring component as well).</p>
<p>From there, you&#8217;re able to substitute for the re-occurring component &#8230; which we know to equal &#8220;2&#8221;.</p>
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		<title>By: Alan Reid</title>
		<link>http://his-best.biz/2008/06/12/mind-bender-15-solution/comment-page-1/#comment-320</link>
		<dc:creator>Alan Reid</dc:creator>
		<pubDate>Sun, 15 Jun 2008 05:06:54 +0000</pubDate>
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		<description>I think you have made an error when you squared the left side of the equation.</description>
		<content:encoded><![CDATA[<p>I think you have made an error when you squared the left side of the equation.</p>
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